欢迎登录材料期刊网

材料期刊网

高级检索

应用动态差示扫描量热(DSC)方法对炭纤维增强树脂基复合材料(CFRP)压力容器树脂体系固化反应进行分析.树脂体系的活化能通过等转化率法获得,假设反应机制服从自催化方程,应用本文中提出的区间法建立了树脂体系固化动力学模型.通过固化过程中温度场实验可知,针对具有超薄金属内衬复合材料压力容器树脂体系,应用区间法建立的固化动力学模型的计算结果与实验结果吻合较好,可以为具有超薄金属内衬的CFRP压力容器温度场、残余应力场的数值模拟提供必要子模型.

参考文献

[1] 任明法,王荣国,陈浩然.具有金属内衬复合材料纤维缠绕容器固化过程的数值模拟[J].复合材料学报,2005,22(4):118-124.Ren Mingfa,Wang Rongguo,Chen Haoran.Numerical simulation of curing process for filament wound pressure vessel with metal liner[J].Acta Materiae Compositae Sinica,2005,22(4):118-124.
[2] 胡荣祖,史启桢.热分析动力学[M].北京:科学出版社,2001:1-18.
[3] Li Zhongjun,Shen Xiaoqing,Feng Xun.Non-isothermal kinetics studies on thermal decomposition of zinc hydroxide carbonate[J].Thermochimica Acta,2005,438(1):102-106.
[4] Sbirrazzuoli N,Girault Y,Elegant L.The Málek method in the kinetic study of polymerization by differential scanning calorimetry[J].Thermochimica Acta,1995,249:179-187.
[5] Mohamed A M,Andrew K G,Samih A H.A comparative study of the thermal reactivities of some transition metal oxalates in selected atmospheres[J].Thermochimica Acta,2004,429(1):57-72.
[6] Litwinienko G,Kasprzycka-Guttman T.A DSC study on thermoxidation kinetics of mustard oil[J].Thermochimica Acta,1998,319(1):185-191.
[7] Dyakonov T,Chen Y,Holland K,et al.Thermal analysis of some aromatic amine cured model epoxy resin systems Ⅰ:Materials synthesis and characterization,cure and post-cure[J].Polymer Degradation and Stability,1996,53(2):217-242.
[8] Carfagna C,Nicolais L,Amendola E.Carfagna Jr,Fillipov A G.Toughening epoxy resins by liquid crystalline polymers[J].Journal of Applied Polymer Science,1992,44(8):1465-1471.
[9] Catalani A,Bonicelli M G.Kinetics of the curing reaction of a diglycidyl ether of bisphenol A with a modified polyamine[J].Thermochimica Acta,2005,438(1):126-129.
[10] Zvetkov V L.Comparative DSC kinetics of the reaction of DGEBA with aromatic diamines I:Non-isothermal kinetic study of the reaction of DGEBA with m-phenylene diamine[J].Polymer,2001,42(16):6687-6697.
上一张 下一张
上一张 下一张
计量
  • 下载量()
  • 访问量()
文章评分
  • 您的评分:
  • 1
    0%
  • 2
    0%
  • 3
    0%
  • 4
    0%
  • 5
    0%